# Initial topology

In general topology and related areas of mathematics, the initial topology (or induced topology[1][2] or weak topology or limit topology or projective topology) on a set ${\displaystyle X}$, with respect to a family of functions on ${\displaystyle X}$, is the coarsest topology on X that makes those functions continuous.

The subspace topology and product topology constructions are both special cases of initial topologies. Indeed, the initial topology construction can be viewed as a generalization of these.

The dual notion is the final topology, which for a given family of functions mapping to a set ${\displaystyle X}$ is the finest topology on ${\displaystyle X}$ that makes those functions continuous.

## Definition

Given a set X and an indexed family (Yi)iI of topological spaces with functions

${\displaystyle f_{i}:X\to Y_{i},}$

the initial topology ${\displaystyle \tau }$  on ${\displaystyle X}$  is the coarsest topology on X such that each

${\displaystyle f_{i}:(X,\tau )\to Y_{i}}$

is continuous.

Explicitly, the initial topology is the collection of open sets generated by all sets of the form ${\displaystyle f_{i}^{-1}(U)}$ , where ${\displaystyle U}$  is an open set in ${\displaystyle Y_{i}}$  for some iI, under finite intersections and arbitrary unions. The sets ${\displaystyle f_{i}^{-1}(U)}$  are often called cylinder sets. If I contains exactly one element, all the open sets of ${\displaystyle (X,\tau )}$  are cylinder sets.

## Examples

Several topological constructions can be regarded as special cases of the initial topology.

## Properties

### Characteristic property

The initial topology on X can be characterized by the following characteristic property:
A function ${\displaystyle g}$  from some space ${\displaystyle Z}$  to ${\displaystyle X}$  is continuous if and only if ${\displaystyle f_{i}\circ g}$  is continuous for each i ∈ I.

Note that, despite looking quite similar, this is not a universal property. A categorical description is given below.

### Evaluation

By the universal property of the product topology, we know that any family of continuous maps ${\displaystyle f_{i}\colon X\to Y_{i}}$  determines a unique continuous map

${\displaystyle f\colon X\to \prod _{i}Y_{i}\,.}$

This map is known as the evaluation map.

A family of maps ${\displaystyle \{f_{i}\colon X\to Y_{i}\}}$  is said to separate points in X if for all ${\displaystyle x\neq y}$  in X there exists some i such that ${\displaystyle f_{i}(x)\neq f_{i}(y)}$ . Clearly, the family ${\displaystyle \{f_{i}\}}$  separates points if and only if the associated evaluation map f is injective.

The evaluation map f will be a topological embedding if and only if X has the initial topology determined by the maps ${\displaystyle \{f_{i}\}}$  and this family of maps separates points in X.

### Separating points from closed sets

If a space X comes equipped with a topology, it is often useful to know whether or not the topology on X is the initial topology induced by some family of maps on X. This section gives a sufficient (but not necessary) condition.

A family of maps {fi: XYi} separates points from closed sets in X if for all closed sets A in X and all x not in A, there exists some i such that

${\displaystyle f_{i}(x)\notin \operatorname {cl} (f_{i}(A))}$

where cl denotes the closure operator.

Theorem. A family of continuous maps {fi: XYi} separates points from closed sets if and only if the cylinder sets ${\displaystyle f_{i}^{-1}(U)}$ , for U open in Yi, form a base for the topology on X.

It follows that whenever {fi} separates points from closed sets, the space X has the initial topology induced by the maps {fi}. The converse fails, since generally the cylinder sets will only form a subbase (and not a base) for the initial topology.

If the space X is a T0 space, then any collection of maps {fi} that separates points from closed sets in X must also separate points. In this case, the evaluation map will be an embedding.

## Categorical description

In the language of category theory, the initial topology construction can be described as follows. Let ${\displaystyle Y}$  be the functor from a discrete category ${\displaystyle J}$  to the category of topological spaces ${\displaystyle \mathrm {Top} }$  which maps ${\displaystyle j\mapsto Y_{j}}$ . Let ${\displaystyle U}$  be the usual forgetful functor from ${\displaystyle \mathrm {Top} }$  to ${\displaystyle \mathrm {Set} }$ . The maps ${\displaystyle f_{j}:X\to Y_{j}}$  can then be thought of as a cone from ${\displaystyle X}$  to ${\displaystyle UY}$ . That is, ${\displaystyle (X,f)}$  is an object of ${\displaystyle \mathrm {Cone} (UY):=(\Delta \downarrow {UY})}$ —the category of cones to ${\displaystyle UY}$ . More precisely, this cone ${\displaystyle (X,f)}$  defines a ${\displaystyle U}$ -structured cosink in ${\displaystyle \mathrm {Set} }$ .

The forgetful functor ${\displaystyle U:\mathrm {Top} \to \mathrm {Set} }$  induces a functor ${\displaystyle {\bar {U}}:\mathrm {Cone} (Y)\to \mathrm {Cone} (UY)}$ . The characteristic property of the initial topology is equivalent to the statement that there exists a universal morphism from ${\displaystyle {\bar {U}}}$  to ${\displaystyle (X,f)}$ , i.e.: a terminal object in the category ${\displaystyle ({\bar {U}}\downarrow (X,f))}$ .
Explicitly, this consists of an object ${\displaystyle I(X,f)}$  in ${\displaystyle \mathrm {Cone} (Y)}$  together with a morphism ${\displaystyle \varepsilon :{\bar {U}}I(X,f)\to (X,f)}$  such that for any object ${\displaystyle (Z,g)}$  in ${\displaystyle \mathrm {Cone} (Y)}$  and morphism ${\displaystyle \varphi :{\bar {U}}(Z,g)\to (X,f)}$  there exists a unique morphism ${\displaystyle \zeta :(Z,g)\to I(X,f)}$  such that the following diagram commutes:

The assignment ${\displaystyle (X,f)\mapsto I(X,f)}$  placing the initial topology on ${\displaystyle X}$  extends to a functor ${\displaystyle I:\mathrm {Cone} (UY)\to \mathrm {Cone} (Y)}$  which is right adjoint to the forgetful functor ${\displaystyle {\bar {U}}}$ . In fact, ${\displaystyle I}$  is a right-inverse to ${\displaystyle {\bar {U}}}$ ; since ${\displaystyle {\bar {U}}I}$  is the identity functor on ${\displaystyle \mathrm {Cone} (UY)}$ .