1906 Major League Baseball season

The 1906 Major League Baseball season was contested from April 12 to October 14, 1906. The Chicago Cubs and Chicago White Sox were the regular season champions of the National League and American League, respectively. The White Sox then defeated the Cubs in the World Series, four games to two.

1906 MLB season
LeagueMajor League Baseball
DurationApril 12 – October 14, 1906
Number of games154
Number of teams16
Pennant Winners
AL championsChicago White Sox
  AL runners-upNew York Highlanders
NL championsChicago Cubs
  NL runners-upNew York Giants
World Series
ChampionsChicago White Sox
  Runners-upChicago Cubs
MLB seasons

Season informationEdit

The Chicago Cubs won a record 116 games while losing only 36. Their .763 winning percentage remains the highest in the modern (two-league) era.[1] They were led offensively by third baseman Harry Steinfeldt whose 176 hits, .327 batting average and 83 RBIs were all a team-best; Steinfeldt also had 29 stolen bases. The Cubs' pitching staff consisted of Ed Reulbach, Carl Lundgren, Mordecai Brown and left-hander Jack Pfiester.




  World Series
  AL Chicago White Sox 4
  NL Chicago Cubs 2



American LeagueEdit

Team Manager Comments
Boston Americans Jimmy Collins and Chick Stahl
Chicago White Sox Fielder Jones
Cleveland Naps Nap Lajoie
Detroit Tigers Bill Armour
New York Highlanders Clark Griffith
Philadelphia Athletics Connie Mack
St. Louis Browns Jimmy McAleer
Washington Senators Jake Stahl

National LeagueEdit

Team Manager Comments
Boston Beaneaters Fred Tenney
Brooklyn Superbas Patsy Donovan
Chicago Orphans Frank Chance
Cincinnati Reds Ned Hanlon
New York Giants John McGraw
Philadelphia Phillies Hugh Duffy
Pittsburgh Pirates Fred Clarke
St. Louis Cardinals John McCloskey


  1. ^ Kramer, Daniel; Adler, David (June 13, 2020). "The best season in every club's history". MLB.com. Retrieved October 9, 2020.
  2. ^ "Today in Baseball History – September 26th". nationalpastime.com/site. Retrieved September 26, 2015.

External linksEdit