1904 Major League Baseball season

The 1904 Major League Baseball season was contested from April 14 to October 10, 1904. The Boston Americans and New York Giants finished atop standings for the American League and National League, respectively. There was no postseason, as the Giants declined to meet the Americans in a World Series.

1904 MLB season
LeagueMajor League Baseball
SportBaseball
DurationApril 14 – October 10, 1904
Number of games154
Number of teams16
Pennant Winners
AL championsBoston Americans
  AL runners-upNew York Highlanders
NL championsNew York Giants
  NL runners-upChicago Cubs
MLB seasons

Regular-season schedules were increased this season from 140 games to 154 games, with each team now playing the other seven teams in the same league 22 times apiece; this scheduling would be used through the 1918 season.

The St. Louis Browns and Detroit Tigers played 11 consecutive games against each other in September—the first six in Detroit and the final five in St. Louis[1]—the most games played consecutively between two teams in major league history.[2]

StandingsEdit

League leadersEdit

  American League National League
Type Name Stat Name Stat
AVG Nap Lajoie .376 Honus Wagner .349
HR Harry Davis 10 Harry Lumley 9
RBI Nap Lajoie 102 Bill Dahlen 80
Wins Jack Chesbro 41 Joe McGinnity 35
ERA Addie Joss 1.59 Joe McGinnity 1.61

No-hittersEdit

PostseasonEdit

No postseason was held this year.

ManagersEdit

EventsEdit

ReferencesEdit

  1. ^ "The 1904 Detroit Tigers Regular Season Game Log". Retrosheet. Retrieved October 9, 2020.
  2. ^ "Games Played by Teams Record Book". Baseball-Almanac.com. Retrieved May 14, 2012.
  3. ^ Pellowski, Michael J (2007). The Little Giant Book of Baseball Facts. United States: Sterling Publishing Co. pp. 352. ISBN 9781402742736.

External linksEdit