1860 United States presidential election in Wisconsin

The 1860 United States presidential election in Wisconsin was held on November 6, 1860. Wisconsin voters chose five electors to the Electoral College, who voted for president and vice president.

United States presidential election, 1860

← 1856 November 6, 1860 1864 →
  Abraham Lincoln O-26 by Hesler, 1860 (cropped).jpg BradyHandy-StephenADouglas restored.jpg
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel V. Johnson
Electoral vote 5 0
Popular vote 86,113 65,021
Percentage 56.59% 42.73%

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

Republican Party candidate Abraham Lincoln won the state with 57% of the popular vote, winning Wisconsin's five electoral votes.

ResultsEdit

United States presidential election in Wisconsin, 1860[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Abraham Lincoln of Illinois Hannibal Hamlin of Maine 86,113 56.59% 5 100.00%
Democratic Stephen A. Douglas of Illinois Herschel Vespasian Johnson of Georgia 65,021 42.73% 0 0.00%
Southern Democratic John C. Breckinridge of Kentucky Joseph Lane of Oregon 888 0.58% 0 0.00%
Constitutional Union John Bell of Tennessee Edward Everett of Massachusetts 161 0.11% 0 0.00%
Total 152,183 100.00% 5 100.00%

ReferencesEdit

  1. ^ "1860 Presidential General Election Results - Wisconsin".