1860 United States presidential election in New Hampshire

The 1860 United States presidential election in New Hampshire took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose five electors of the Electoral College, who voted for president and vice president.

1860 United States presidential election in New Hampshire

← 1856 November 2, 1860 1864 →
  Abraham Lincoln O-26 by Hesler, 1860 (cropped).jpg BradyHandy-StephenADouglas restored.jpg
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel Vespasian Johnson
Electoral vote 5 0
Popular vote 37,519 25,887
Percentage 56.90% 39.26%

United States presidential election in New Hampshire, 1860 results by county.svg
Results by county

Lincoln

  40-49%
  50-59%
  60-69%

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

New Hampshire was won by Republican candidate Abraham Lincoln, who won the state by 17.61%.

ResultsEdit

1860 United States presidential election in New Hampshire[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Abraham Lincoln of Illinois Hannibal Hamlin of Maine 37,519 56.90% 5 100.00%
Democratic Stephen A. Douglas of Illinois Herschel Vespasian Johnson of Georgia 25,887 39.29% 0 0.00%
Southern Democratic John C. Breckinridge of Kentucky Joseph Lane of Oregon 2,125 3.22% 0 0.00%
Constitutional Union John Bell of Tennessee Edward Everett of Massachusetts 412 0.62% 0 0.00%
Total 65,943 100.00% 5 100.00%

ReferencesEdit

  1. ^ "1860 Presidential General Election Results - New Hampshire".