1860 United States presidential election in Michigan

The 1860 United States presidential election in Michigan took place on November 6, 1860, as part of the 1860 United States presidential election. Michigan voters chose six representatives, or electors, to the Electoral College, who voted for president and vice president.[1]

1860 United States presidential election in Michigan

← 1856 November 6, 1860 1864 →
  Abraham Lincoln O-26 by Hesler, 1860 (cropped).jpg BradyHandy-StephenADouglas restored.jpg
Nominee Abraham Lincoln Stephen A. Douglas
Party Republican Democratic
Home state Illinois Illinois
Running mate Hannibal Hamlin Herschel V. Johnson
Electoral vote 6 0
Popular vote 88,450 64,889
Percentage 57.23% 41.99%

Michigan Presidential Election Results 1860.svg
Results by county

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

Michigan was won by Illinois Representative Abraham Lincoln (RKentucky), running with Senator Hannibal Hamlin, with 57.23% of the popular vote, against Senator Stephen A. Douglas (DVermont), running with 41st Governor of Georgia Herschel V. Johnson, with 43.97% of the popular vote.[1]

ResultsEdit

1860 United States presidential election in Michigan[1]
Party Candidate Votes %
Republican Abraham Lincoln 88,450 57.23%
Democratic Stephen A. Douglas 64,889 41.99%
Southern Democratic John C. Breckinridge 805 0.52%
Constitutional Union John Bell 405 0.26%
Total votes 154,549 100%

ReferencesEdit

  1. ^ a b c "1860 Presidential Election Results Michigan".