1860 United States presidential election in Georgia

The 1860 United States presidential election in Georgia took place on November 6, 1860, as part of the 1860 United States presidential election. Georgia voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.

United States presidential election in Georgia, 1860

← 1856 November 6, 1860 1868 →
  John C Breckinridge-04775-restored.jpg John-bell-brady-handy-cropped restored.jpg BradyHandy-StephenADouglas restored.jpg
Nominee John C. Breckinridge John Bell Stephen A. Douglas
Party Southern Democratic Constitutional Union Democratic
Home state Kentucky Tennessee Illinois
Running mate Joseph Lane Edward Everett Herschel V. Johnson
Electoral vote 10 0 0
Popular vote 52,176 42,960 11,581
Percentage 48.89% 40.26% 10.85%

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

Georgia was won by the 14th Vice President of the United States John Breckenridge (SDKentucky), running with Senator Joseph Lane, with 48.89% of the popular vote, against Senator John Bell (CUTennessee), running with the Governor of Massachusetts Edward Everett, with 40.26% of the popular vote and the 15th Senator Stephen A. Douglas (DVermont), running with 41st Governor of Georgia Herschel V. Johnson, with 10.85% of the popular vote.

Republican Party candidate Abraham Lincoln was not on the ballot in the state. This was the last time until 1964 that Georgia did not vote for the national Democratic Party.

ResultsEdit

United States presidential election in Georgia, 1860[1]
Party Candidate Votes %
Southern Democratic John C. Breckinridge 52,176 48.89%
Constitutional Union John Bell 42,960 40.26%
Democratic Stephen A. Douglas 11,581 10.85%
Total votes 106,717 100%

ReferencesEdit

  1. ^ "1860 Presidential Election Results Georgia".