1860 United States presidential election in Alabama

The 1860 United States presidential election in Alabama took place on November 6, 1860, as part of the 1860 United States presidential election. Alabama voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.

1860 United States presidential election in Alabama

← 1856 November 6, 1860 1868 →
  John C Breckinridge-04775-restored.jpg John-bell-brady-handy-cropped restored.jpg BradyHandy-StephenADouglas restored.jpg
Nominee John Breckenridge John Bell Stephen A. Douglas
Party Southern Democratic Constitutional Union Democratic
Home state Kentucky Tennessee Illinois
Running mate Joseph Lane Edward Everett Herschel V. Johnson
Electoral vote 9 0 0
Popular vote 48,669 27,835 13,618
Percentage 54.00% 30.89% 15.11%

President before election

James Buchanan

Elected President

Abraham Lincoln

Alabama was won by the 14th Vice President of the United States John Breckenridge (SDKentucky), running with Senator Joseph Lane, with 54.00% of the popular vote, against Senator John Bell (CUTennessee), running with the Governor of Massachusetts Edward Everett, with 30.89% of the popular vote and the 15th Senator Stephen A. Douglas (DIllinois), running with 41st Governor of Georgia Herschel V. Johnson, with 15.11% of the popular vote.

Republican Party candidate Abraham Lincoln was not on the ballot in the state.


1860 United States presidential election in Alabama[1]
Party Candidate Votes %
Southern Democratic John C. Breckinridge 48,669 54.00%
Constitutional Union John Bell 27,835 30.89%
Democratic Stephen A. Douglas 13,618 15.11%
Total votes 90,122 100%


  1. ^ "1860 Presidential Election Results Alabama". Cite has empty unknown parameter: |1= (help)