1808 United States presidential election in New York

The 1808 United States presidential election in New York took place between November 4 and December 7, 1808, as part of the 1808 United States presidential election. The state legislature chose 19 representatives, or electors to the Electoral College, who voted for President and Vice President.

1808 United States presidential election in New York

← 1804 November 4 - December 7, 1808 1812 →
  James Madison.jpg George Clinton by Ezra Ames.jpg
Nominee James Madison George Clinton
Party Democratic-Republican Democratic-Republican
Home state Virginia New York
Running mate George Clinton James Madison/ James Monroe
Electoral vote 13 6
Percentage 68.38% 31.62%

President before election

Thomas Jefferson

Elected President

James Madison

During this election, New York split its 19 electoral votes among two Democratic Republican candidates. 13 electoral votes went to Secretary of State James Madison while the remaining 6 went to incumbent Vice President George Clinton. Clinton was also supported by a group of New York Democratic-Republicans for president even though he had remained the party's official vice presidential candidate.[1]

This would be the final election until 1972 in which New York did not have the largest number of electors in the Electoral College.

See alsoEdit


  1. ^ Kaminski, John P. (1993). George Clinton: Yeoman Politician of the New Republic. Rowman & Littlefield. pp. 281–288. Retrieved 12 October 2015.